feb 2015 problem 5

uil/aplus-february-2015/5/Favorite.MD

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+# Favorite
+
+Run my solution on **[repl.it](https://repl.it/@Xevion/A-Computer-Science-February-2015-Favorite)!**
+
+I most definitely complicated this as much as possible, although, the code is still very, very small.
+
+I simply had two literal string primitive arrays setup with team member names and actor names. Actor or Actress could be varied using a expected prefix of `M` (for *actor*) or `F` (for *actress*).
+
+When printing, I simply substring'd it away using a ternary operator with two options (`"actor" : "actress"`), and then output it alongside a `.substring(1)` (which starts at index 1 and includes everything including and following it).
+
+`String.format` comes in handy here when it comes to regulating a more complex set of values quickly, I recommend those who don't use it to get more familiar (it's very, very useful when formatting/rounding floating point numbers off).

uil/aplus-february-2015/5/Favorite.java

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+import static java.lang.System.out;
+
+class Main {
+  public static void main(String[] args) {
+      String[] names = new String[]{"John", "Sarah", "Mark"};
+      String[] actors = new String[]{"MJohn Wayne", "FMeryl Streep", "MAl Pacino"};
+      assert names.length == actors.length : "Team Names array and Actor/Actress names array must be equal in length.";
+
+      for(int i = 0; i < names.length; i++) {
+          out.println(
+              String.format("My name is %s, and my favorite movie %s is %s.",
+                names[i], actors[i].substring(0, 1).equals("M") ? "actor" : "actress", actors[i].substring(1) 
+              )
+          );
+      }
+  }
+}