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ysu-acm solves and icpc A & B
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import sys, os
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# Read the data
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path = os.path.join(sys.path[0], 'input')
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data = open(path, 'r').read().split('\n')
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data = list(map(int, data))
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assert all(map(lambda x : x >= 1, data))
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print('\n\n'.join('\n'.join('*' * x for x in range(n, 0, -1))for n in data))
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5
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100
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import os, sys, math
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path = os.path.join(sys.path[0], 'input')
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data = open(path, 'r').read().split('\n')
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# To keep with the times of 1991, we will use the constraints of Python2 for max integers
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maxInt = 9223372036854775807
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def extend(n):
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res = 1
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for x in range(2, n + 1):
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res = x * res
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return res
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x = 100
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print(extend(x))
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print(math.log(extend(x), 10))
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23
berkely/1991 YSU-ACM High School Programming Contest/3/input
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berkely/1991 YSU-ACM High School Programming Contest/3/input
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THIS IS THE ('FIRST') LINE IN THE SAMPLE FILE!!!!
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ANY CHARACTERS CAN BE IN THE FILE%^$*.(")...
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('THIS PART OF THE FILE SHOULD NOT BE CHANGED')
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'(BUT THIS PART SHOULD 123........('...............
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NUMBERS, 1234567890, ARE OK. OK?
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import re, string, os, sys
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pattern = r'([\s\S]*)(\(.*\))([\s\S]*)'
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def main():
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path = os.path.join(sys.path[0], 'input')
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mapping = str.maketrans(string.ascii_uppercase, string.ascii_uppercase[::-1])
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print(string.ascii_uppercase)
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print(string.ascii_uppercase[::-1])
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data = open(path, 'r').read()
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matches = re.findall(pattern, data)[0]
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result = ''
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for match in matches:
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result += match if match.startswith('(') else match.translate(mapping)
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print(result)
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These problems honestly seem extraordinarily easy, but it's likely do to the constraints of computer programming back then. Kind of cheating, using Python.
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[Official Link](https://people.eecs.berkeley.edu/~hilfingr/programming-contest/ysu_91.pdf) | [GitHub Mirror](./ysu_91.pdf)
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[Official Link](https://people.eecs.berkeley.edu/~hilfingr/programming-contest/ysu_91.pdf) | [GitHub Mirror](./ysu_91.pdf)
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## Notice
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Inputs / Outputs are retyped since the PDF is obsfucated.
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## Progress
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#1 : Solved
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#2 : **Unsolved**
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#3 : **Unsolved**
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#4 : Solved
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#5 : **Unsolved**
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90 80 4
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60 35 25
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50 140 35
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195 165 25
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195 40 40
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import sys, os, math
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# Pythagorean Distance Formula
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def pyth(x1, y1, x2, y2):
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return math.sqrt(((x1 - x2) ** 2) + ((y1 - y2) ** 2))
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def dist(spot1, spot2):
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return pyth(spot1[0], spot1[1], spot2[0], spot2[1])
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def main():
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def parse(dat):
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return list(map(int, dat.split()))
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path = os.path.join(sys.path[0], 'input')
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data = open(path, 'r').read().split('\n')
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listeners = []
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for dataset in data:
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listeners.append(parse(dataset))
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spy = listeners.pop(0)
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distances = sorted()
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if __name__ == "__main__":
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main()
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987654321
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import os, sys
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def harshad(n):
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return (n % sum(map(int, list(str(n))))) == 0
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def main():
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inputs = [os.path.join(sys.path[0], 'inputs', x) for x in
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os.listdir(os.path.join(sys.path[0], 'inputs'))]
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inputs = [int(open(path).read()) for path in inputs]
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for i in inputs:
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while not harshad(i):
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i += 1
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print(i)
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if __name__ == "__main__":
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main()
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# 2018 ICPC East Central North America Regional Contest
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[Report](http://acm-ecna.ysu.edu/PastResults/2018/home.html) | []
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## Notice
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Most of these problems seem modestly easy, if I'm being honest.
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## Progress
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#1 : Unsovled
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#2 : **Solved**
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