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4 lines
360 B
Python
4 lines
360 B
Python
def find_anagrams(word, candidates):
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word, lowercandidates = word.lower(), list(map(lambda item : item.lower(), candidates))
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build = {char : word.count(char) for char in word.lower()}
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return [candidates[index] for index, candidate in enumerate(lowercandidates) if {char : candidate.count(char) for char in candidate} == build and candidate != word] |