spiral matrix and prime factors exercise

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Xevion
2019-07-24 14:37:17 -05:00
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{"track":"python","exercise":"prime-factors","id":"8594f50d455a42c2bcaaf99a23da57ec","url":"https://exercism.io/my/solutions/8594f50d455a42c2bcaaf99a23da57ec","handle":"Xevion","is_requester":true,"auto_approve":false}

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# Prime Factors
Compute the prime factors of a given natural number.
A prime number is only evenly divisible by itself and 1.
Note that 1 is not a prime number.
## Example
What are the prime factors of 60?
- Our first divisor is 2. 2 goes into 60, leaving 30.
- 2 goes into 30, leaving 15.
- 2 doesn't go cleanly into 15. So let's move on to our next divisor, 3.
- 3 goes cleanly into 15, leaving 5.
- 3 does not go cleanly into 5. The next possible factor is 4.
- 4 does not go cleanly into 5. The next possible factor is 5.
- 5 does go cleanly into 5.
- We're left only with 1, so now, we're done.
Our successful divisors in that computation represent the list of prime
factors of 60: 2, 2, 3, and 5.
You can check this yourself:
- 2 * 2 * 3 * 5
- = 4 * 15
- = 60
- Success!
## Exception messages
Sometimes it is necessary to raise an exception. When you do this, you should include a meaningful error message to
indicate what the source of the error is. This makes your code more readable and helps significantly with debugging. Not
every exercise will require you to raise an exception, but for those that do, the tests will only pass if you include
a message.
To raise a message with an exception, just write it as an argument to the exception type. For example, instead of
`raise Exception`, you should write:
```python
raise Exception("Meaningful message indicating the source of the error")
```
## Running the tests
To run the tests, run the appropriate command below ([why they are different](https://github.com/pytest-dev/pytest/issues/1629#issue-161422224)):
- Python 2.7: `py.test prime_factors_test.py`
- Python 3.4+: `pytest prime_factors_test.py`
Alternatively, you can tell Python to run the pytest module (allowing the same command to be used regardless of Python version):
`python -m pytest prime_factors_test.py`
### Common `pytest` options
- `-v` : enable verbose output
- `-x` : stop running tests on first failure
- `--ff` : run failures from previous test before running other test cases
For other options, see `python -m pytest -h`
## Submitting Exercises
Note that, when trying to submit an exercise, make sure the solution is in the `$EXERCISM_WORKSPACE/python/prime-factors` directory.
You can find your Exercism workspace by running `exercism debug` and looking for the line that starts with `Workspace`.
For more detailed information about running tests, code style and linting,
please see [Running the Tests](http://exercism.io/tracks/python/tests).
## Source
The Prime Factors Kata by Uncle Bob [http://butunclebob.com/ArticleS.UncleBob.ThePrimeFactorsKata](http://butunclebob.com/ArticleS.UncleBob.ThePrimeFactorsKata)
## Submitting Incomplete Solutions
It's possible to submit an incomplete solution so you can see how others have completed the exercise.

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def factors(value):
factors, n = [], 2
while value > 1:
while value % n == 0:
factors.append(n)
value /= n
n += 1
return factors

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import unittest
from prime_factors import factors
# Tests adapted from `problem-specifications//canonical-data.json` @ v1.1.0
class PrimeFactorsTest(unittest.TestCase):
def test_no_factors(self):
self.assertEqual(factors(1), [])
def test_prime_number(self):
self.assertEqual(factors(2), [2])
def test_square_of_a_prime(self):
self.assertEqual(factors(9), [3, 3])
def test_cube_of_a_prime(self):
self.assertEqual(factors(8), [2, 2, 2])
def test_product_of_primes_and_non_primes(self):
self.assertEqual(factors(12), [2, 2, 3])
def test_product_of_primes(self):
self.assertEqual(factors(901255), [5, 17, 23, 461])
def test_factors_include_a_large_prime(self):
self.assertEqual(factors(93819012551), [11, 9539, 894119])
if __name__ == '__main__':
unittest.main()

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{"track":"python","exercise":"simple-cipher","id":"6d5485599e744039a9d97ab829528b7f","url":"https://exercism.io/my/solutions/6d5485599e744039a9d97ab829528b7f","handle":"Xevion","is_requester":true,"auto_approve":false}

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# Simple Cipher
Implement a simple shift cipher like Caesar and a more secure substitution cipher.
## Step 1
"If he had anything confidential to say, he wrote it in cipher, that is,
by so changing the order of the letters of the alphabet, that not a word
could be made out. If anyone wishes to decipher these, and get at their
meaning, he must substitute the fourth letter of the alphabet, namely D,
for A, and so with the others."
—Suetonius, Life of Julius Caesar
Ciphers are very straight-forward algorithms that allow us to render
text less readable while still allowing easy deciphering. They are
vulnerable to many forms of cryptoanalysis, but we are lucky that
generally our little sisters are not cryptoanalysts.
The Caesar Cipher was used for some messages from Julius Caesar that
were sent afield. Now Caesar knew that the cipher wasn't very good, but
he had one ally in that respect: almost nobody could read well. So even
being a couple letters off was sufficient so that people couldn't
recognize the few words that they did know.
Your task is to create a simple shift cipher like the Caesar Cipher.
This image is a great example of the Caesar Cipher:
![Caesar Cipher][1]
For example:
Giving "iamapandabear" as input to the encode function returns the cipher "ldpdsdqgdehdu". Obscure enough to keep our message secret in transit.
When "ldpdsdqgdehdu" is put into the decode function it would return
the original "iamapandabear" letting your friend read your original
message.
## Step 2
Shift ciphers are no fun though when your kid sister figures it out. Try
amending the code to allow us to specify a key and use that for the
shift distance. This is called a substitution cipher.
Here's an example:
Given the key "aaaaaaaaaaaaaaaaaa", encoding the string "iamapandabear"
would return the original "iamapandabear".
Given the key "ddddddddddddddddd", encoding our string "iamapandabear"
would return the obscured "ldpdsdqgdehdu"
In the example above, we've set a = 0 for the key value. So when the
plaintext is added to the key, we end up with the same message coming
out. So "aaaa" is not an ideal key. But if we set the key to "dddd", we
would get the same thing as the Caesar Cipher.
## Step 3
The weakest link in any cipher is the human being. Let's make your
substitution cipher a little more fault tolerant by providing a source
of randomness and ensuring that the key contains only lowercase letters.
If someone doesn't submit a key at all, generate a truly random key of
at least 100 characters in length.
## Extensions
Shift ciphers work by making the text slightly odd, but are vulnerable
to frequency analysis. Substitution ciphers help that, but are still
very vulnerable when the key is short or if spaces are preserved. Later
on you'll see one solution to this problem in the exercise
"crypto-square".
If you want to go farther in this field, the questions begin to be about
how we can exchange keys in a secure way. Take a look at [Diffie-Hellman
on Wikipedia][dh] for one of the first implementations of this scheme.
[1]: https://upload.wikimedia.org/wikipedia/commons/thumb/4/4a/Caesar_cipher_left_shift_of_3.svg/320px-Caesar_cipher_left_shift_of_3.svg.png
[dh]: http://en.wikipedia.org/wiki/Diffie%E2%80%93Hellman_key_exchange
## Should I use random or secrets?
Python, as of version 3.6, includes two different random modules.
The module called `random` is pseudo-random, meaning it does not generate
true randomness, but follows an algorithm that simulates randomness.
Since random numbers are generated through a known algorithm, they are not truly random.
The `random` module is not correctly suited for cryptography and should not be used,
precisely because it is pseudo-random.
For this reason, in version 3.6, Python introduced the `secrets` module, which generates
cryptographically strong random numbers that provide the greater security required for cryptography.
Since this is only an exercise, `random` is fine to use, but note that **it would be
very insecure if actually used for cryptography.**
## Exception messages
Sometimes it is necessary to raise an exception. When you do this, you should include a meaningful error message to
indicate what the source of the error is. This makes your code more readable and helps significantly with debugging. Not
every exercise will require you to raise an exception, but for those that do, the tests will only pass if you include
a message.
To raise a message with an exception, just write it as an argument to the exception type. For example, instead of
`raise Exception`, you should write:
```python
raise Exception("Meaningful message indicating the source of the error")
```
## Running the tests
To run the tests, run the appropriate command below ([why they are different](https://github.com/pytest-dev/pytest/issues/1629#issue-161422224)):
- Python 2.7: `py.test simple_cipher_test.py`
- Python 3.4+: `pytest simple_cipher_test.py`
Alternatively, you can tell Python to run the pytest module (allowing the same command to be used regardless of Python version):
`python -m pytest simple_cipher_test.py`
### Common `pytest` options
- `-v` : enable verbose output
- `-x` : stop running tests on first failure
- `--ff` : run failures from previous test before running other test cases
For other options, see `python -m pytest -h`
## Submitting Exercises
Note that, when trying to submit an exercise, make sure the solution is in the `$EXERCISM_WORKSPACE/python/simple-cipher` directory.
You can find your Exercism workspace by running `exercism debug` and looking for the line that starts with `Workspace`.
For more detailed information about running tests, code style and linting,
please see [Running the Tests](http://exercism.io/tracks/python/tests).
## Source
Substitution Cipher at Wikipedia [http://en.wikipedia.org/wiki/Substitution_cipher](http://en.wikipedia.org/wiki/Substitution_cipher)
## Submitting Incomplete Solutions
It's possible to submit an incomplete solution so you can see how others have completed the exercise.

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from string import ascii_lowercase as low
class Cipher(object):
def __init__(self, key=None):
self.key = key
self.shift = 27 - (sum([low.index(char) for char in self.key]) % 25)
shifted = low[self.shift:] + low[:self.shift]
print(low)
print(shifted)
self.encode_ = str.maketrans(low, shifted)
self.decode_ = str.maketrans(shifted, low)
def encode(self, text):
return text.translate(self.encode_)
def decode(self, text):
return text.translate(self.decode_)
x = list(zip('iamapandabear', 'ldpdsdqgdehdu'))
x = sorted(dict.fromkeys(x))
x =
from pprint import PrettyPrinter
print = PrettyPrinter().pprint
# c = Cipher('d' * 18)
# print(c.encode('iamapandabear'))

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import unittest
import re
from simple_cipher import Cipher
# Tests adapted from `problem-specifications//canonical-data.json` @ v2.0.0
class SimpleCipherTest(unittest.TestCase):
# Utility functions
def setUp(self):
try:
self.assertRaisesRegex
except AttributeError:
self.assertRaisesRegex = self.assertRaisesRegexp
def assertRaisesWithMessage(self, exception):
return self.assertRaisesRegex(exception, r".+")
class RandomKeyCipherTest(SimpleCipherTest):
def test_can_encode(self):
cipher = Cipher()
plaintext = 'aaaaaaaaaa'
self.assertEqual(cipher.encode(plaintext), cipher.key[:len(plaintext)])
def test_can_decode(self):
cipher = Cipher()
plaintext = 'aaaaaaaaaa'
self.assertEqual(cipher.decode(cipher.key[:len(plaintext)]), plaintext)
def test_is_reversible(self):
cipher = Cipher()
plaintext = 'abcdefghij'
self.assertEqual(cipher.decode(cipher.encode(plaintext)), plaintext)
def test_key_is_only_made_of_lowercase_letters(self):
self.assertIsNotNone(re.match('^[a-z]+$', Cipher().key))
class SubstitutionCipherTest(SimpleCipherTest):
def test_can_encode(self):
cipher = Cipher('abcdefghij')
self.assertEqual(cipher.encode('aaaaaaaaaa'), cipher.key)
def test_can_decode(self):
cipher = Cipher('abcdefghij')
self.assertEqual(cipher.decode(cipher.key), 'aaaaaaaaaa')
def test_is_reversible(self):
cipher = Cipher('abcdefghij')
plaintext = 'abcdefghij'
self.assertEqual(cipher.decode(cipher.encode(plaintext)), plaintext)
def test_can_double_shift_encode(self):
plaintext = 'iamapandabear'
cipher = Cipher(plaintext)
self.assertEqual(cipher.encode(plaintext), 'qayaeaagaciai')
def test_can_wrap_on_encode(self):
cipher = Cipher('abcdefghij')
self.assertEqual(cipher.encode('zzzzzzzzzz'), 'zabcdefghi')
def test_can_wrap_on_decode(self):
cipher = Cipher('abcdefghij')
self.assertEqual(cipher.decode('zabcdefghi'), 'zzzzzzzzzz')
def test_can_encode_messages_longer_than_key(self):
cipher = Cipher('abc')
self.assertEqual(cipher.encode('iamapandabear'), 'iboaqcnecbfcr')
def test_can_decode_messages_longer_than_key(self):
cipher = Cipher('abc')
self.assertEqual(cipher.decode('iboaqcnecbfcr'), 'iamapandabear')
if __name__ == '__main__':
unittest.main()

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{"track":"python","exercise":"spiral-matrix","id":"e351192377fc41329076c9d6636ef233","url":"https://exercism.io/my/solutions/e351192377fc41329076c9d6636ef233","handle":"Xevion","is_requester":true,"auto_approve":false}

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# Spiral Matrix
Given the size, return a square matrix of numbers in spiral order.
The matrix should be filled with natural numbers, starting from 1
in the top-left corner, increasing in an inward, clockwise spiral order,
like these examples:
###### Spiral matrix of size 3
```text
1 2 3
8 9 4
7 6 5
```
###### Spiral matrix of size 4
```text
1 2 3 4
12 13 14 5
11 16 15 6
10 9 8 7
```
## Exception messages
Sometimes it is necessary to raise an exception. When you do this, you should include a meaningful error message to
indicate what the source of the error is. This makes your code more readable and helps significantly with debugging. Not
every exercise will require you to raise an exception, but for those that do, the tests will only pass if you include
a message.
To raise a message with an exception, just write it as an argument to the exception type. For example, instead of
`raise Exception`, you should write:
```python
raise Exception("Meaningful message indicating the source of the error")
```
## Running the tests
To run the tests, run the appropriate command below ([why they are different](https://github.com/pytest-dev/pytest/issues/1629#issue-161422224)):
- Python 2.7: `py.test spiral_matrix_test.py`
- Python 3.4+: `pytest spiral_matrix_test.py`
Alternatively, you can tell Python to run the pytest module (allowing the same command to be used regardless of Python version):
`python -m pytest spiral_matrix_test.py`
### Common `pytest` options
- `-v` : enable verbose output
- `-x` : stop running tests on first failure
- `--ff` : run failures from previous test before running other test cases
For other options, see `python -m pytest -h`
## Submitting Exercises
Note that, when trying to submit an exercise, make sure the solution is in the `$EXERCISM_WORKSPACE/python/spiral-matrix` directory.
You can find your Exercism workspace by running `exercism debug` and looking for the line that starts with `Workspace`.
For more detailed information about running tests, code style and linting,
please see [Running the Tests](http://exercism.io/tracks/python/tests).
## Source
Reddit r/dailyprogrammer challenge #320 [Easy] Spiral Ascension. [https://www.reddit.com/r/dailyprogrammer/comments/6i60lr/20170619_challenge_320_easy_spiral_ascension/](https://www.reddit.com/r/dailyprogrammer/comments/6i60lr/20170619_challenge_320_easy_spiral_ascension/)
## Submitting Incomplete Solutions
It's possible to submit an incomplete solution so you can see how others have completed the exercise.

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# Two lines, dude. ez.
def spiral_matrix(size):
return [] if size < 1 else Matrix(size).matrix
# Class for a pathfinding based spiral generation
class Matrix:
def __init__(self, size):
self.size = size
self.matrix = [[None for y in range(size)] for x in range(size)]
self.i = 1
self.cur = (0, 0)
self.cardinals = [(0, 1), (1, 0), (-1, 0), (0, -1)]
self.dir_index = 0
self.loop()
# Loop that builds the spiral matrix
def loop(self):
# While the current number is less than the maximum number
while self.i < (self.size ** 2):
# If the next position is not valid, turn
if not self.valid(self.nextpos):
self.dir_index = (self.dir_index + 1) % 4
else:
self.access()
self.cur = self.nextpos
self.access()
# Access a position and increment the counter
def access(self):
self.matrix[self.cur[0]][self.cur[1]] = self.i
self.i += 1
# Just the current direction (as an offset)
@property
def direction(self):
return self.cardinals[self.dir_index]
# Next position for access based on the current direction
@property
def nextpos(self):
return (self.cur[0] + self.direction[0], self.cur[1] + self.direction[1])
# Determine whether a position is valid to be approached
def valid(self, pos):
return self.validxy(pos[0], pos[1]) and not self.matrix[pos[0]][pos[1]]
# Determine whether a position is
def validxy(self, x, y):
return x >= 0 and x < self.size and y >= 0 and y < self.size
# Printable Matrix with proper character space justification
def __repr__(self):
return '\n'.join([' '.join(map(lambda item : str(item or '?').rjust(len(str(self.size ** 2))), sub)) for sub in self.matrix])

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import unittest
from spiral_matrix import spiral_matrix
# Tests adapted from `problem-specifications//canonical-data.json` @ v1.1.0
class SpiralMatrixTest(unittest.TestCase):
def test_empty_spiral(self):
self.assertEqual(spiral_matrix(0), [
])
def test_trivial_spiral(self):
self.assertEqual(spiral_matrix(1), [
[1]
])
def test_spiral_of_size_2(self):
self.assertEqual(spiral_matrix(2), [
[1, 2],
[4, 3]
])
def test_spiral_of_size_3(self):
self.assertEqual(spiral_matrix(3), [
[1, 2, 3],
[8, 9, 4],
[7, 6, 5]
])
def test_spiral_of_size_4(self):
self.assertEqual(spiral_matrix(4), [
[1, 2, 3, 4],
[12, 13, 14, 5],
[11, 16, 15, 6],
[10, 9, 8, 7]
])
def test_spiral_of_size_5(self):
self.assertEqual(spiral_matrix(5), [
[1, 2, 3, 4, 5],
[16, 17, 18, 19, 6],
[15, 24, 25, 20, 7],
[14, 23, 22, 21, 8],
[13, 12, 11, 10, 9]
])
if __name__ == '__main__':
unittest.main()